Right! its on its way, I figured id make the thread! this module took a bit of teething, so I’m sorry for the wait but surprisingly still keeping to a module a month!!! give or take a week here and there.
I’m putting together the documentation and videos etc for it today/tomorrow.
everything including the listing should be up on Friday. fingers crossed!!
it comes with the CV12 chip with slightly modified code including return to bass characteristics, defaulting on the mode 4 channel Mono, and also C as 0v (the standard actually has A as 0v), I bought a bulk from Midimuso and will include with the listing, and also it comes with the 2 4504’s as it was pointed out to me that they need to be Texas instrument ones, as other manufacturers 4504’s showed slightly erratic behaviour. so to save some head scratching I got a whole bunch of them too.
(or more likely, the design depends on undefined behaviour (I mean, we’ve already seen the rather creative use of a non-regulating LM317 in the original muso ))
EDIT: Wait, the reference schematics use MC14504, but that’s not a Texas component? Confused.
but yes that’s is also very true! I mean it doesn’t seem to. and to be honest I have not tried it with other brands and I may very well do so!± infact im going to order some and see what happens.
I may aswell see what midimuso is on about. before I question the voodoo gods!±!!
The 74HC14 is fine for driving the MIDI THRU outputs.
Surprisingly it might be a bit marginal for driving the LED’s transistor, which pulls about (5-0.7)/1k = 4.3mA, but the 74HC14 is still better than the 74LS14 which is only rated for 0.4mA for a high output.
I would just replace that 1k resistor by 1.2K to be on the safe side. Shouldn’t affect the LED’s brightness significantly.
EDIT: I was going off the Texas Instrument data sheet, according to Tayda’s web page, the 74HC14 can drive ±5.2mA so it’s OK as-is with the 1K resistor. The 74LS14 on the other hand could use a 12K resistor… which would still probably give a plenty bright LED as the transistor would still be saturated.
))
