Decouple filter from input resistance

I build my first couple of oscillators using inverters and the super simple oscillator layout. Next I wanted to try a filter and built a very simple passive RC low pass. I noticed that it worked well with the inverter-based oscillators but not the super simple oscillator. I guess this is because the latter has a 100k ohms resistor on the output. So when I plug in my filter, the 100k add to the R of the filter. Since mine uses a 10k pot this makes the filter pretty useless, right?
So I need a way to decouple the filter’s input from any resistance (or capacitor) I guess that might be in series of the circuit I want to put into the filter. I guess this cannot be done with passive filters.
I found a design for a simple active inverting filter, where the capacitor is not in series with the input but on the feed-back loop of the op-amp. This would solve my problem, but now I do not know where to put the potentionmeter in a way that I can adjust the cutoff frequency without altering the gain of the opamp at the same time.
Does any of this make sense and are there any simple (one op-amp) filter layouts that can do what I need?

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It is hard to visualize your circuit but your problem is not unique and has a few different solutions.

  1. Can you add a simple transistor or OP-AMP buffer between the oscillator and the passive filter? The op-amp buffer is really easy and will provide a very very high input impedance and a low output impedance. The op-amp filter implementation is good but it may have a low input impedance depending on the design and may not fix your problem.
  2. Can you scale the values up in the filter so that filter input impedance is 1Meg instead of 100k? That may work well enough.
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Thanks, using the op-amp as buffer really solves the problem. I couldn’t try the second suggestion because I do not have the right parts.

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