Eurorack power with 16 pin header - using +5V supply

Hello everyone!

I’m just starting in module design and I have a question regarding the circuit for powering a eurorack module. Not the power supply itself, but the circuit that goes in the module.

In the designs I’ve done until now, I use a 10 pin header with the following connections:

Screen Shot 2024-07-12 at 20.41.40

However, right now I’m designing a module that has some digital components, so I would like to use a 16 pin header so I can use the +5V output of the supply. Should I do something similar to the schematic above for the +5V, or can I connect it directly to the components?

The components that I’m using are some flip-flops and low noise switches. So, high frequency interference shouldn’t be a problem (I think).

As I said I’m quite new to this, so I’m still figuring this stuff out. Also, I haven’t tested the circuit yet but I want to sort this out before getting the components.

Your advice is really welcome! Thanks!

The point of the Schottky diodes is to provide protection against power reversal occurring when the power connection is backwards — if there’s a shrouded header it’s impossible to plug the ribbon connector in the “other” way, but it can and does happen sometimes that the ribbon cable has been made wrong, or the power bus board, or the connection to the bus board. And of course if it’s an unshrouded header the connection can be backwards there.

With a 10-pin connector, if it’s backwards you have what should be this:

instead being this:

Ground is OK, but you have +12 V where you should have -12 V and vice versa. With the schematic you show the diodes block current flow in the wrong direction so you’re protected.

But with a 16 pin connector connected backwards you have what should be this:

image
instead being this:

You have:

  • -12 V on what should be Gate — if your module doesn’t use the Gate from the header, this isn’t a problem
  • Ground on what should be CV — if your module doesn’t use the CV from the header, this isn’t a problem
  • Ground on what should be 5 V — not a major problem
  • Ground on what should be +12 V — not a major problem
  • +12 V on what should be Ground and
  • +5 V on what should be Ground and
  • CV on what should be Ground — in other words you’ve shorted +12 V, +5 V, and CV together, this is a problem
  • Gate on what should be -12 V — could be a problem if Gate is used somewhere in your synth, it will put positive voltages on what should be a negative rail

A Schottky diode on the -12 V pin would protect against positive Gate voltages, but nothing much can save you from the fact a reversed connector will short +12 V, +5 V, and CV together. You definitely don’t want to be putting diodes on what should be the ground rail. Maybe you can use polyswitch fuses or 10Ω resistors — separate ones on each pair of ground pins, then tie them together on the other side? Doesn’t sound like a great idea to me, but maybe.

I guess if I were doing it I’d just cross my fingers, leave out the diodes, and hope I never got the power connection backwards. To protect against shorts with the connector not reversed you could use fuses or 10Ω resistors on the +12 V, +5 V, and -12 V pins, but I figure if I check for shorts before plugging it in the first time, there’s unlikely to be a short at any later time.

Another option would be to use a 10 pin header — with the power reversal diodes — and then add a +5 V regulator to your PCB design and power the digital stuff with that. That’s really what I do, but then I do it in Kosmo format which only uses 10 pin headers anyway — my synth power supply and bus boards have no provision for +5 V.

The 10 µF capacitors are for bypass and there definitely should be one to ground on each of the +12 V, +5 V, and -12 V rails.

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Thanks! That was really helpful. I didn’t realize that I would short -12V and +5V if the connector is reversed. Then I think I’ll just be careful and make sure it is always correctly plugged.

Thank you very much!!

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I prefer 10-pin + built-in regulator for that safety aspect.
One more thing is that even if the power header standard had a safer physical arrangement, the voltage drop of a diode on a 5V rail would be bad enough you could no longer power a microcontroller with it.

Voltage drop using a 1N5817 is only about 290 mV. An ATmega328P (as in many Arduinos) can run on as low as 2.7 V. I haven’t tested extensively but Blink seems to work fine on an Uno with a 5 V supply connected through a 1N5817 to the 5 V pin.

Of course that means the microcontroller outputs are 4.7 V, not 5 V, so if you’re counting on it to generate 5 V gates you might run into trouble. Not having the diode on the rail does seem preferable, though not unworkable.

I just had another idea, but I’m not sure if it would work. What if I buffer the +5V signal from the bus so instead of drawing current from +5V I get it from the +12V -12V supply? Do you think that could work?

I won’t discard the regulator method, but since I have some space constraints I don’t know if I can fit it. My board is quite full right now, but I have an unused opamp that could do the job.

Also, I have discarded the use of diodes. I’m the only person that is going to use the module, so I’ll just be super careful not to plug it backwards. And I’m not powering a microcontroller, just some small ICs so I don’t mind destroying a couple of them to get it just right. The problem would be damaging the power supply.

Op amps can’t deliver very much current. It’s not in the TL07x datasheet but I wouldn’t count on more than about 20 mA, and as you get close to the limit the output voltage will sag. You might get away with it but if it were me I’d find some way to use a regulator. You only need a TO92 or SOT-23 package and one or two capacitors.